Answer:
451977.40113 N/C
Explanation:
[tex]\epsilon_0[/tex] = Permittivity of free space = [tex]8.85\times 10^{-12}\ F/m[/tex]
[tex]\sigma[/tex] = Surface charge density = [tex]4\ pc/mm^2[/tex]
Electric field near the surface of a charged conductor is given by
[tex]E=\dfrac{\sigma}{\epsilon_0}\\\Rightarrow E=\dfrac{4\times 10^{-12}\times 10^{6}}{8.85\times 10^{-12}}\\\Rightarrow E=451977.40113\ N/C[/tex]
The electric field is 451977.40113 N/C
