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Sorin chose a three-digit number and doubled it. Jiao chose a two-digit number. Carlos subtracted Jiao’s number from Sorin’s product. What is the greatest number Carlos can get?
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Answer:

The number is 1988.

Step-by-step explanation:

Carlo's outcome will be the greatest if Sorin's number will be the highest and Jiao's number is the lowest.

Sorin choose a three digit number, the highest three digit number is 999.

After doubled the number, 999, the outcome will be 1998.

Jiao chooses two-digit number, the lowest two-digit number is 10.

Hence, the greatest number that Carlo can get is (1998 - 10) = 1988.

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