What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative one-ninth) Superscript n minus 1 Negative twelve-ninths Negative one-ninths 1 12

Respuesta :

Answer:

12

Step-by-step explanation:

The given geometric series is

[tex] \sum_{n = 1}^{ \infty} 12( { - \frac{1}{9} })^{n - 1} [/tex]

We want to determine the first term of this geometric series.

Recall that the explicit formula is

[tex] a_{n} = 12( { - \frac{1}{9} })^{n - 1} [/tex]

To find the first term, we put n=1 to get:

[tex]a_{1} = 12( { - \frac{1}{9} })^{1 - 1} [/tex]

This gives us:

[tex]a_{1} = 12( { - \frac{1}{9} })^{0}[/tex]

[tex]a_{1} = 12(1) = 12[/tex]

Therefore the first term is 12

iriesm

Answer:

12

Step-by-step explanation:

The last option, C is the answer. I just took the quiz :D