I will have "x" represent the unknown number, or you could use a "?", doesn't matter.
[tex]8\leq \frac{x}{-4}[/tex] [8 is less than or equal to (≤) the quotient (÷) of a number and -4, so the number is being divided by -4]
If you need to solve this, you need to isolate/get the variable "x" by itself in the inequality:
[tex]8\leq \frac{x}{-4}[/tex] Multiply -4 on both sides to get rid of the fraction and get "x" by itself
[tex](-4)8\geq \frac{x}{-4} (-4)[/tex] When you multiply/divide by a negative number, you flip the sign (< >)
-32 ≥ x [-32 is greater than or equal to x, or x is less than or equal to -32]
