Answer:
[tex]\dfrac{p^2+9p+2}{p^2-49}[/tex]
Step-by-step explanation:
Problems like this require that you recognize that the denominator of the right term is a factor of the denominator of the left term. That is, you're supposed to know how to recognize and factor the difference of two squares.
[tex]\dfrac{5-p}{49-p^2}+\dfrac{p+1}{p-7}=\dfrac{p-5}{p^2-49}+\dfrac{p+1}{p-7}\\\\=\dfrac{p-5}{(p-7)(p+7)}+\dfrac{p+1}{p-7}\cdot\dfrac{p+7}{p+7}\\\\=\dfrac{(p-5)+(p+1)(p+7)}{(p-7)(p+7)}=\dfrac{p-5+p^2+8p+7}{p^2-49}=\dfrac{p^2+9p+2}{p^2-49}[/tex]
