Respuesta :
Answer:
a. r = 5t
b. [tex]A = \pi r^2[/tex]
c. [tex]A = \pi (5t)^2[/tex]
d. [tex]A = 25\pi t^2[/tex]
Step-by-step explanation:
a. Since the radius is increasing at a constant rate of 5 cm per second.
r = 5t
where r is the radius at time t (seconds)
b. Area of circle [tex]A = \pi r^2[/tex]
c. We can substitute r = 5t into the area formula to have
[tex]A = \pi r^2 = \pi (5t)^2[/tex]
d. In expand form
[tex]A = \pi (5t)^2 = 25\pi t^2[/tex]
a. The expression is R = 5t
b. The area of the circle in terms of R is A = πR²
c. The area of the circle in terms of t is A = π(5t)²
d. The area of the circle in terms of t in the expanded form is A = 25π×t²
Linear system
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
Circle
It is a locus of a point drawn at an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
Given
R = 5t where R is the radius, and t be the time.
Thus, the answer will be
a. The expression will be
R = 5t
b. The area of the circle in terms of R will be
Area = πR²
c. The area of the circle in terms of t will be
Area = πR²
Area = π(5t)²
d. The area of the circle in terms of t in the expanded form will be
Area = πR²
Area = π(5t)²
Area = 25π×t²
More about the linear system link is below.
https://brainly.com/question/20379472
