Answer:
233 g
Explanation:
Let's consider the following reaction.
CaCO₃ → CaO + CO₂
We can establish the following relations:
The mass of carbon dioxide produced from 530 g of calcium carbonate is:
[tex]530gCaCO_{3}\frac{1molCaCO_{3}}{100.09gCaCO_{3}} ,\frac{1molCO_{2}}{1molCaCO_{3}} .\frac{44.01gCO_{2}}{1molCO_{2}} =233gCO_{2}[/tex]
233 gram of carbon dioxide gas is produced from the decomposition of calcium carbonate.
[tex]CaCO_3\rightarrow CaO + CO_2[/tex]
From the above decomposition, we can say that the molar ratio of calcium carbonate to carbon dioxide is 1:1.
The molar mass of calcium carbonate is 100.09 g/mol.
The molar ratio of calcium carbonate to carbon dioxide is 1:1.
The molar mass of carbon dioxide is 44.01 g/mol
The mass of carbon dioxide produced from 530 g of calcium carbonate is:
[tex]{530\ gCaCO_3}\times\frac{1molCaCO_3}{100gCaCO_3} \times\frac{1molCO_2}{1molCaCO_3} \times\frac{44.01\ gCO_2}{1molCO_2} =233\ gCO_2[/tex]
So, the 233 g [tex]CO_2[/tex] will be produced.
Find more information about the decomposition and production here
brainly.com/question/883757
