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Consider the following mechanism for the formation of tert-butanol: (CH_3)_3CBr(aq) rightarrow (Ch_3)_3 C^+ (aq) + Br^- (aq) (CH_3)_3 C^+ (aq) + OH^- (aq) rightarrow (CH_3)_3 COH(aq) Write the chemical equation of the overall reaction: Are there any intermediates in this mechanism? yes no If there are intermediates, write down their chemical formulas. Put a comma between each chemical formula, if there's more than one.

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Answer:

The mechanism is in the attached file. The reaction intermediates are the following: C4H8O, C4H9O

Explanation:

Terbutanol is a tertiary alcohol. It is one of the four isomers of butanol. It is a transparent liquid (or a colorless solid, depending on the temperature), with an odor similar to camphor. It is very soluble in water and ethanol.

The scheme shows a protonation of the double bond and the nucleophilic attack of the water to the carbocation, then it loses a proton and the terbutanol is formed.

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