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Calculate to three significant digits the density of carbon monoxide gas at exactly -5c and 1 atm exactly . You can assume carbon monoxide gas behaves as an ideal gas under these conditions.

Respuesta :

Answer:

1.77 g/L.

Explanation:

Molar mass of CO2 = 12 + (16*2)

= 44 g/mol.

Using ideal gas equation,

V/n = R*T/P

Where,

R = 0.082 L.atm/mol.K

T = 30°C

= 273 + 30

= 303 K

P = 1 atm

V/n = (0.082 * 303)/1

= 24.845 L/mol

Density = mass * volume

Density = molar volume/molar mass

= 44/24.845

= 1.77 g/L

Eduard22sly

The density of carbon monoxide gas at exactly -5 °C and 1 atm is 1.27 g/L

We'll begin by calculating the volume of the gas. This can be obtained by using the ideal gas equation as follow:

Temperature (T) = –5 °C = –5 + 273 = 268 K

Pressure (P) = 1 atm

Number of mole (n) = 1 mole

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1 × 0.0821 × 268

V = 22.0028 L

  • Next, we shall determine the mass of the gas

Molar mass of CO = 12 + 16 = 28 g/mol

Mole of CO = 1 mole

Mass of CO =?

Mass = mole × molar mass

Mass of CO = 1 × 28

Mass of CO = 28 g

  • Finally, we shall determine the density of the gas

Mass = 28 g

Volume = 22.0028 L

Density =?

[tex]Density = \frac{mass}{volume} \\ \\ Density = \frac{28}{22.0028} \\ \\ Density =1.27 \: g/L[/tex]

Therefore, the density of the gas is 1.27 g/L

Learn more: https://brainly.com/question/17327692

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