Respuesta :
Te question is incomplete, the complete question is:
[tex]2Mg+O_2\rightarrow 2MgO,[/tex]
[tex]Rate=k[Mg][O2]^2[/tex]
What is the overall reaction order?
What are the units of the rate constant k for this reaction?What would happen to the rate if [Mg] were doubled? What would happen to the rate if [tex][O_2][/tex] were doubled? Would these 2 rates stay the same,double, triple, or quadruple?
Explanation:
Order of the reaction is sum of power of reactant species present in a rate equation of the sample.
So, the rate of the given reaction is :
[tex]R=k[Mg][O2]^2[/tex]
Order of the reaction = 1 + 2 = 3
Order of the reaction is 3.
The rate if [Mg] were doubled = R'
[tex]R'=k[2Mg][O_2]^2=2k[Mg][O_2]^2=2R[/tex]
The rate of the reaction will get doubled when [Mg] is doubled.
The rate if [tex][O_2][/tex] were doubled = R''
The rate of the reaction will get quadruple when [tex][O_2][/tex] is doubled.
The order of the given reaction has been 3.
The double concentration of Mg results, the rate of reaction to be double.
The double concentration of Oxygen results, the rate of reaction to be Quadrupole.
The complete equation for the reaction has been given as:
[tex]\rm 2\;Mg\;+\;O_2\;\rightarrow\;2\;MgO[/tex]
The rate of reaction has been defined as the rate of consumption of reactants or rate of appearance of products. The relation between the concentration of species and rate of reaction has been given by the order of reaction.
Order of Reaction
The order of reaction for the given equation has been calculated by the sum of superscript of the concentration of each reactant. The order of reaction has been given as:
[tex]R=k[Mg][O_2]^2[/tex]
The order of reaction has been:
[tex]\rm Order=1+2\\Order=3[/tex]
The order of the given reaction has been 3.
The double concentration of Mg in the reaction mixture has been resulted in the rate of reaction (R')as:
[tex]R'=[2\;Mg][O_2]^2\\R'=2R[/tex]
The double concentration of Mg results, the rate of reaction to be double.
The double concentration of oxygen in the reaction mixture has been resulted in the rate of reaction (R") as:
[tex]R"=k[Mg][2\;O_2]^2\\R"=4R[/tex]
The double concentration of Oxygen results, the rate of reaction to be Quadrupole.
For more information about rate of reaction, refer to the link:
https://brainly.com/question/8592296
