Let Ohm be the region bounded by the function y = -x^2 + 2x and the x-axis. This region is revolved about the y-axis. Find the volume of the solid formed.
a. 4 pi/3
b. 8 pi/3
c. 11 pi/3
d. 512 pi/15
e. 16 pi/15
f. None

Respuesta :

Answer:

Option b

Step-by-step explanation:

The intersection of the given curve with x axis are

when y =0

i.e. when

[tex]-x^2 + 2x=0\\x=0,2[/tex]

Since rotated about y axis we use method of cylinders

Volume = [tex]\int\limits^2_0 {2\pi xy} \, dx \\=2\pi \int\limits^2_0 x(-x^2+2x)dx\\= 2\pi(\frac{-x^3}{3} +x^2)\\= \frac{8\pi}{3}[/tex]

option b is right