Answer:
[tex]t = 11.70\ s[/tex]
Explanation:
given,
Height of the jet above ground = 4500 m
speed of the jet = 650 m/s
Speed of sound = 331 m/s
now, calculating mach angle
[tex]sin\theta =\dfrac{v}{v_s}[/tex]
[tex]sin\theta =\dfrac{331}{650}[/tex]
[tex]\theta = 30.61^0[/tex]
now, shock wave to travel 4500 m
we know.
[tex]t = \dfrac{distance}{velocity}[/tex]
[tex]t = \dfrac{4500}{v_s\ tan\theta}[/tex]
[tex]t = \dfrac{4500}{650\times tan\ 30.61^0}[/tex]
[tex]t = 11.70\ s[/tex]
Hence, time taken by the shock wave to reach ground is equal to 11.7 s.
