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Please save the program with the name ‘palindrome.c’Write a functionand its prototypewhichreturn true if the string parameter is a palindrome.Apalindrome is any "word" which is the same forward and backward, eg, "radar", "noon", "20011002", ... The function should return false if the argument is not a palindrome. Please try to use functions that we have learned in class.This is the output example:

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teobguan2019

Answer:

The solution code is written in C.

  1. #include <stdio.h>
  2. #include <string.h>
  3. #include <stdbool.h>
  5. bool isPalindrome(char str[])
  6. {
  7.    int length = strlen(str) ;
  8.    bool status = true;
  9.    int i;
  10.    
  11.    for(i = 0; i < length / 2; i++){
  12.      
  13.        if(str[i] != str[length - 1 - i]){
  14.            status = false;
  15.            return status;
  16.        }
  17.    }
  18.    
  19.    return status;
  20. }

Explanation:

Firstly, we need to include libraries stdio, string and stdbool (Line 1 -3).

Next, we create a function isPalindrome that take one string parameter and return a boolean value (Line 5).

We use function strlen to get the length to the input string (Line 7). At this point, let's set our status as true (Line 8).

We create a for-loop to traverse through the characters inside the input string (Line 11). Within the loop, we set a condition that compare the first letter to the letter started from the last index (Line 13). If the letters are not matched, this means the input string is not a palindrome and set the status as false and return it as output (Line 14 - 15).

Otherwise, the for-loop will just terminate without running the statements within the if-block and return status as true (Line 19).