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Consider two positively charged particles, one of charge q₀ (particle 0) fixed at the origin, and another of charge q₁ (particle 1) fixed on the y-axis at (0,d₁,0). What is the net force [tex]\vec{F}[/tex] on particle 0 due to particle 1?
Express your answer (a vector) using any or all of k, q₀, q₁, d₁, [tex]\hat{i}[/tex], [tex]\hat{j}[/tex], and [tex]\hat{k}[/tex].

Respuesta :

Answer:

Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by

[tex]F=k\frac{q_0q_1}{r^2}[/tex]

where r is the distance between the charges & k is the Coulomb's constant

k=1/(4*ε_0*π)

k=9*10^9

the distance between the charges in this question is d_1

hence the magnitude of the force exerted by q_0 on q_1 is given by

[tex]F=k\frac{q_0q_1}{d_1^2}[/tex]

due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form

[tex]F=k\frac{q_0q_1}{d_1^2} j[/tex]

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