The time intervals are missing in the question.You can put any time in equation v(t) which I have solved
Answer:
[tex]v(t)=52-1.66t[/tex]
Explanation:
Given data
Velocity=52 m/s
Height h(t)=52t-0.83t²
To find
Average velocity
Solution
As we know that velocity is first derivative of distance with respect to time
So
[tex]v(t)=\frac{dh(t)}{dt}\\ v(t)=\frac{d}{dt}[52t-0.83t^{2} ]\\ v(t)=52-1.66t[/tex]
After one second the velocity is
[tex]v(t)=52-1.66t\\at\\t=1seconds\\v(1)=52-1.66(1)\\v(1)=56.33m/s[/tex]
