Catherine is creating a triangular banner for her school's football team. She wants the height of the banner to be 4 times as tall as the width of the base of the triangle. If she wants the total area of the banner to be 8 feet squared (8ft2), how wide should the base of the triangle be in feet?

Respuesta :

Answer:

The base of the triangle should be 2 feet

Step-by-step explanation:

Let the base of the triangle be y  

She wants the height of the banner to be 4 times as tall as the width of the base of the triangle

So height  is  =  [tex]4 \times y[/tex] = 4y

Now we know that the area of the triangle is  =[tex]\frac{1}{2} (base \times height)[/tex]

we  also know that total area of the banner is 8 feet squared

Then

[tex]8 = \frac{1}{2}(y \times 4y)[/tex]

[tex]8 = \frac{4y^2}{2}[/tex]

[tex]16 = 4y^2[/tex]

[tex]\frac{16}{4} = y^2[/tex]

[tex]4 = y^2[/tex]

[tex]y = \sqrt{4}[/tex]

y = 2

Width if the base of the triangle is 2 feet