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A charge of 11.748 nC is uniformly distributed along the x-axis from −2 m to 2 m . What is the electric potential (relative to zero at infinity) of the point at 5 m on the x-axis? The value of the Coulomb constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of V

Respuesta :

Answer:

electric potential  =  22.36 volt

Explanation:

given data

charge Q =  11.748 nC

distance d = 5 - 2 = 3 m

length = 2 + 2 = 4 m

Coulomb constant = 8.98755 × 109 N·m²/C ²

solution

electric potential is express as

electric potential  = [tex]\frac{Q}{4\pi \epsilon _o L}[/tex] [tex]ln(1+\frac{L}{d})[/tex]   ..............1

electric potential  = [tex]\frac{KQ}{L} ln(1+\frac{L}{d})[/tex]  

put here value

electric potential  = [tex]\frac{8.98755\times 10^9\times 11.748\times 10{-9}}{4} ln(1+\frac{4}{3})[/tex]  

electric potential  =  22.36 volt

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