Answer:
F = 150.00 N
Explanation:
Let F1 = 220 N, θ1 = 0° ( on the x-axis)
F2 = 150 N and θ2 = 30°
Solution:
For F1
F1x = F1 cos θ = 220 N cos 0° = 220 N
F1y= F1 sin θ = 220 N sin 0° = 0 N
For F2
F2x = F2 cos θ = 150 N cos 30° = 129.904 N
F2y= F2 sin θ = 150 N sin 30° = 75 N
Fx = F1x + F2x = 220 N + 129.904 N
Fx = 349.904 N
Fy = F1y + F2y = 0 N+ 75 N = 75 N
Now resultant vector formula
F = square root ( Fx² + Fy²)
F= square root ( (129.904 N)² + (75N)²)
F=square root (22500.049)
F = 150.00 N