Answer:
The answer to this question is 1,013 Joules or 1.013 kJ.
Explanation:
This process is an isobaric process as pressure is constant throughout.
Work done by gas expansion, W
= P Δ V ; (where P = pressure, ΔV = change in volume)
W = 10 atm (10 - 1 ) L
W = 10 L. atm ⇒ 10 × [tex]\frac{101.3 J}{ 1 L.atm}[/tex]
W = 1,013 Joules ≈ 1. 01 kJ.
