In the following acid-base reactions, identify the spectator ions, if any:
(i) Cesium hydroxide(aq) + nitric acid(aq) =>
(ii) Calcium hydroxide(aq) + acetic acid(aq) =>
a.
(i) Cs+ and NO3-
(ii) no spectator ions
b.
(i) Cs+ and NO3-
(ii) H+ and OH-
c.
(i) no spectator ions
(ii) H+ and OH-
d.
(i) Cs+ and NO3-
(ii) Ca2+ and acetate ion.
e.
(i) no spectator ions
(ii) no spectator ions

Respuesta :

Answer : The correct option is, (d)

(i) [tex]Cs^+,\text{ and }NO_3^-[/tex]

(ii) [tex]Ca^{2+},\text{ and }CH_3COO^-[/tex]

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(i) The balanced molecular equation will be,

[tex]CsOH(aq)+HNO_3(aq)\rightarrow CsNO_3(aq)+H_2O(l)[/tex]

The complete ionic equation in separated aqueous solution will be,

[tex]Cs^+(aq)+OH^{-}(aq)+H^{+}(aq)+NO_3^{-}(aq)\rightarrow Cs^+(aq)+NO^{3-}(aq)+H_2O(l)[/tex]

In this equation the species [tex]Cs^+,\text{ and }NO_3^-[/tex] are the spectator ions.

(ii) The balanced molecular equation will be,

[tex]Ca(OH)_2(aq)+2CH_3COOH(aq)\rightarrow Ca(CH_3COO)_2(aq)+H_2O(l)[/tex]

The complete ionic equation in separated aqueous solution will be,

[tex]Ca^{2+}(aq)+2OH^{-}(aq)+2H^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Ca^{2+}(aq)+2CH_3COO^{-}(aq)+H_2O(l)[/tex]

In this equation the species [tex]Ca^{2+},\text{ and }CH_3COO^-[/tex] are the spectator ions.

Hence, the correct option is, (d)

(i) [tex]Cs^+,\text{ and }NO_3^-[/tex]

(ii) [tex]Ca^{2+},\text{ and }CH_3COO^-[/tex]