Answer:
Pr(A) = 0.55
Pr (B) = 0.55
Pr (C) = 0.3025
Pr (D) = 0.166375
Step-by-step explanation:
Given that:
Pr(tail) = 55% = 0.55
Pr (head) = 1 - Pr(tails)
Pr (head) = 1 - 0.55
Pr (head) = 0.45
Pr(A) = first flip is a tail = 0.55
Pr (B) = second flip is a tail
Pr(B) = Pr(head on the first flip and tail on the second flip) + P(tail on both flips)
Pr (B) = (0.45 × 0.55) + ( 0.55 × 0.55)
Pr (B) = 0.2475 + 0.3025
Pr (B) = 0.55
Pr (C) = 0.55 x 0.55
= 0.3025
Pr (D) = 0.55 x 0.55 x 0.55
= 0.166375
From above; we can conclude that Pr (A) and Pr (B) are independent.
Answer:
A= 0.55,B=0.55,C=0.3025,D=0.1664; A and B are independent
Step-by-step explanation:
probability of tail:0.55
probability of not a tail: 0.45
A= P(tail and tail and tail)+P(tail and not tail and tail) + P(tail and not tail and not tail)+P(tail and tail and not tail)
A= 0.55×0.55×0.55+0.55×0.45×0.55+0.55×0.45×0.45+0.55×0.55×0.45
A=0.55
B= P(tail and tail and tail)+P(not tail and tail and tail)+P(tail and tail and not tail)+P(not tail and tail and not tail)
B=0.55×0.55×0.55+0.45×0.55×0.55+0.55×0.55×0.45+0.45×0.55×0.45
B= 0.55
C=P(tail and tail and tail)+P(tail and tail and not tail)
C=0.55×0.55×0.55+0.55×0.55×0.45
C=0.3025
D=P(tail and tail and tail)
D=0.55×0.55×0.55
D=0.1664
For events to be independent, the probability of occurance of one event must not be dependent on the outcome of other event.
Here, first and second flip have to be tail for C and D to happen. However, if first flip is a tail then second slip may or may not be a tail!
