contestada

On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.0∘F∘F to 45.0∘F∘F in just 2 minutes. What was the temperature change in Celsius degrees?

Respuesta :

Answer:

The change in temperature, [tex]\Delta T=9.45^{\circ} C[/tex]

Explanation:

Given that,

The temperature in Spearfish, South Dakota, rose from [tex]-4^{\circ} F\ to\ 45^{\circ} F[/tex] in just 2 minutes. We need to find the temperature change in Celsius degrees. Change in temperature is given by final temperature minus initial temperature such that,

[tex]\Delta T=T_f-T_i\\\\\Delta T=45-(-4)\\\\\Delta T=49^{\circ}F[/tex]

The relation between degrees Celsius and degrees Fahrenheit is given by :

[tex]F=1.8C+32[/tex]

Here, F = 49 degrees

[tex]49=1.8C+32\\\\\Delta T=9.45^{\circ} C[/tex]

So, the change in temperature is 9.45 degree Celsius. Hence, this is the required solution.