Answer:
work done in the process is 0 J.
Explanation:
Given :
Initial pressure of system , [tex]p_i=10\ kPa.[/tex]
Final pressure of system , [tex]p_f=20\ kPa.[/tex]
Volume of system , [tex]V=5\ m^3.[/tex]
We know, In thermodynamics work done is defined as :
[tex]W=P\Delta V[/tex]
Here , P is pressure and [tex]\Delta V[/tex] is change in volume.
Now, coming back to question , it state that the process is isochoric .
Therefore, change in volume , [tex]\Delta V=0.[/tex]
Putting value of [tex]\Delta V=0[/tex] in above equation we get ,
W = 0 J.
Therefore , work done in this process is 0 J.
Hence, this is the required solution.