Answer : The molarity after a reaction time of 5.00 days is, 0.109 M
Explanation :
The integrated rate law equation for second order reaction follows:
[tex]k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)[/tex]
where,
k = rate constant = [tex]9.7\times 10^{-6}M^{-1}s^{-1}[/tex]
t = time taken = 5.00 days
[A] = concentration of substance after time 't' = ?
[tex][A]_o[/tex] = Initial concentration = 0.110 M
Now put all the given values in above equation, we get:
[tex]9.7\times 10^{-6}=\frac{1}{5.00}\left (\frac{1}{[A]}-\frac{1}{(0.110)}\right)[/tex]
[tex][A]=0.109M[/tex]
Hence, the molarity after a reaction time of 5.00 days is, 0.109 M
