A survey of athletes at a high school is conducted, and the following facts are discovered: 29% of the athletes are football players, 63% are basketball players, and 24% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that he is either a football player or a basketball player?

Respuesta :

Answer:

The probability that he is either a football player or a basketball player is [tex]\frac{11}{25}[/tex].

Step-by-step explanation:

29% athletes are football players and 24% of the athletes are both football and basketball player.

Hence, (29 - 24) = 5% athletes are football player but not basketball player.

Similarly, (63 - 24) = 39% athletes are basketball player but not a football player.

Hence, the required probability is [tex]\frac{5 + 39}{100} = \frac{44}{100} = \frac{11}{25}[/tex].

Answer:

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Step-by-step explanation: