Answer:
a) current in the second wire is 5.60A
b) opposite directions
Explanation:
a) We need to find the current of wire, the magnitude of the force per unit length between the two wires carrying current I and I¹ is given by
[tex]\frac{F}{L} = \frac{U_0I^1}{2\pi r} \\\\I^1 = \frac{F2\pi r}{LU_0I}[/tex]
[tex]= (3.6 * 10^-^5)\frac{2\pi (0.02)}{4\pi * 10^-^7)(0.64)} \\= 5.60A[/tex]
b) knowing that for a two parallel conductor carrying current in the same direction attracts each other, and for a two parallel conductors carrying carying current in opposite direction repels eachother.
therefore, since the two wire repel each other then the current in the second wire must flow in the opposite direction of the current in the first wire.
