Given Information:
Current = I = 28 A
distance between wires = r = 2.0 m
Required Information:
Magnetic field = B = ?
Answer:
B = 12x10⁻⁶ T
Step-by-step explanation:
Biot-Savart Law is given by
B = μ₀I/2πr
Where μ₀ is the permeability of free space, I is the current flowing through the wire and B is the magnitude of the magnetic field produced.
We are asked to find the magnetic field midway between the wires so r/2 = 1
B = 4πx10⁻⁷*28/2π*1
B = 6x10⁻⁶ T
since the same amount of current flows in both wires therefore, equal amount of magnetic field will be produced in both wires
B = 2*6x10⁻⁶ T
B = 12x10⁻⁶ T
Therefore, the net magnetic field midway between the two wires is 12x10⁻⁶ T.
