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Which of these systems of equations has no solution? Select three that apply. 14x + 7y = 30 14x + 7y = 40 17x – 10y = 38 17x –12y = 38 7x – 15y = 26 8x – 15y = 26 18x + 5y = –42 19x + 6y = –44 11x – 2y = –25 11x – 2y = –20 5x + 9y = 34 5x + 9y = 27

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Answer:

Step-by-step explanation:

We are given a system of equations and have to find out which do not have solution

[tex]i) 14x + 7y = 30\\ 14x + 7y = 40[/tex]

these two are parallel lines and hence will never intersect.  So no solution

[tex]ii) 17x - 10y = 38\\ 17x -12y = 38[/tex]

Subtracting we get y =0 and x =38/17 hence solution exist.

[tex]iii) 7x -15y = 26 \\8x - 15y = 26[/tex]

Subtract to get x =0 and y = -26/15.  Hence solution exist.

iv) [tex]18x + 5y = -42\\ 19x + 6y = -44[/tex]

these two are non parallel hence intersection so solution is there.

[tex]11x - 2y = -25\\ 11x -2y = -20[/tex]

these two are parallel lines and hence no solution

[tex]5x + 9y = 34 \\5x + 9y = 27[/tex]

these two are parallel lines and hence no solution

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