Answer: The required discriminant of the given quadratic equation is 8.
Step-by-step explanation: We are given to find the discriminant of the following quadratic equation :
[tex]-x^2+4x-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We know that
the discriminant of a quadratic equation of the form [tex]ax^2+bx+c=0,~a\neq 0[/tex] is given by
[tex]D=b^2-4ac.[/tex]
In the given quadratic equation, we have
a = -1, b = 4 and c = -2.
Therefore, the discriminant of the given quadratic equation is
[tex]D=b^2-4ac=4^2-4\times(-1)\times(-2)=16-8=8.[/tex]
Thus, the required discriminant of the given quadratic equation is 8.
