Hey need some help with this problem, its trigonometry with right triangles using SohCahToa if you can give me a hand it would be greatly appreciated

For the given triangle, the value of x equals 30.9892 units.
Step-by-step explanation:
Step 1:
In the triangle, the angle is 40°, the opposite side has a length of 26 units, the adjacent side has a length of x units while the hypotenuse is not given.
To determine the value of x, we determine the value of the tan of the given triangle.
To calculate the tan of angle A we divide the opposite side's length by the the adjacent side's length.
[tex]tan A = \frac{oppositeside}{adjacent side}.[/tex]
Step 2:
The length of the opposite side = 26 units.
The length of the adjacent side = x units.
[tex]tan A = \frac{oppositeside}{adjacent side}, tan 40 = 0.8390, tan A = \frac{26}{x} .[/tex]
[tex]0.8390 = \frac{26}{x} , x = \frac{26}{0.8390} = 30.9892.[/tex]
So x measures 30.9892 units.