Respuesta :

Answer:

  • 1.6%

Explanation:

Percent dissociation is the amount of the substance dissociated per 100 parts.

Determine how much dissociate from a 0.55 M solution.

1. Write the dissociation equation:

          C₃H₅O₃H ⇄ C₃H₅O₃H⁻ + H⁺

2. Build the ICE (initial, change, equilibrium) table:

 

        C₃H₅O₃H ⇄ C₃H₅O₃H⁻ + H⁺

I          0.55M             0              0

C           - x                 +x             +x

E         0.55 - x            x              x

3. Write the equilibrium equation and calculate x

  • Keq = x² / (0.55 - x)
  • 1.4 × 10⁻⁴ = x² / (0.55 -x)

  • x² + 0.00014x - 0.000077 = 0

   Use the quadratic equation:

       [tex]x=\dfrac{-0.00014\pm\sqrt{0.00014^2-4(1)(-0.000077)}}{2(1)}[/tex]

The positve value is x = 0.0087

4. Calculate the percent dissociation, α

  • α = (0.0087/0.55) × 100

  • α = 1.6% ← answer