26. The graph of linear function fpasses through the point (1,-6) and has a slope of -2

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09-03-2020
Mathematics

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26. The graph of linear function fpasses through the point (1,-6) and has a slope of -2

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carlosego carlosego · Answer 1 · 2020-03-15T01:50:54+01:00

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

[tex]y = mx + b[/tex]

Where:

m: It is the slope of the line

b: It is the cut point with the y axis

We have according to the data:

[tex]m = -2[/tex]

Thus, the equation is of the form:

[tex]y = -2x + b[/tex]

We substitute the given point:

[tex](x, y) :( 1, -6)\\-6 = -2 (1) + b\\-6 = -2 + b\\-6 + 2 = b\\b = -4[/tex]

Finally, the equation is:

[tex]y = -2x-4[/tex]

Answer:

[tex]y = -2x-4[/tex]

calculista calculista · Answer 2 · 2020-03-15T01:54:04+01:00

calculista calculista

15-03-2020

Answer:

[tex]y=-2x-4[/tex]

Step-by-step explanation:

step 1

Write the linear equation in point slope form

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=-2\\(x1,y1)=(1,-6)[/tex]

substitute

[tex]y+6=-2(x-1)[/tex]

step 2

Convert to slope intercept form

[tex]y=mx+b[/tex]

we have

[tex]y+6=-2(x-1)[/tex]

isolate the variable y

[tex]y+6=-2x+2[/tex]

[tex]y=-2x+2-6\\y=-2x-4[/tex]

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