By Friday he would have read for 145 hours.
Step-by-step explanation:
Given:
Number of hours Anders read on Monday =15 minutes
Every day he increases the reading time by 7 minutes
This reading time forms an arithmetic progression
Here,
The first value is "a"=15
Common difference "d"=7
Number of days from Monday to Friday =5, Thus n=5
Number of minutes he read by Friday=sum up to 5 terms of the AP=S5
Number of times he read on Friday =a5
[tex]a_{n} =a+(n-1)d\\\\a_{5} =a+(n-1)d\\=15+(n-1)7\\=15+(51)7\\=15+4\times7\\=15+28=43\\\\\\S_{n} =n/2(a+a_{n} )\\\\=5/2(15+43)=2.5\times 58=145\ hours[/tex]
Thus By Friday he would have read for 145 hours.
