The electric potential at the center of curvature of the rod is 6.21 V.
What is electric field potential?
Electric field potential is the work done in bringing a charge from infinity a certain point in the electric field.
The electric potential at the center of curvature of the rod is calculated as follows;
[tex]V = \frac{kQ}{R} \\\\V = \frac{9\times 10^9 \times 25.6 \times 10^{-12}}{0.0371} \\\\V = 6.21 \ V[/tex]
Thus, the electric potential at the center of curvature of the rod is 6.21 V.
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