Explanation:
In order to determine the work done, we will first calculate the internal energy as follows.
[tex]\Delta U = \frac{5}{2}nRT[/tex]
= [tex]\frac{5}{2} \times \frac{2 \times 1.02}{29} \times 8.314 \times 298[/tex]
= 0.171 kJ
Now, we know that relation between internal energy and pressure according to the first law of thermodynamics is as follows.
[tex]\Delta U[/tex] = q + w
Since, in the given situation heat energy (q) is equal to 0. Therefore,
[tex]\Delta U[/tex] = w
= 0.171 kJ
Thus, we can conclude that minimum work that must be supplied to accomplish this compression process is 0.171 kJ.
