The pressure drop along a length of artery is 100 Pa, the radius is 10 mm, and the flow is laminar. The average speed of the blood is 15 mm/s. (a) What is the net force on the blood in this section of artery

Respuesta :

Explanation:

The given data is as follows.

   radius (r) = [tex]10 mm = 10 \times 10^{-3} m[/tex]   (as 1 mm = [tex]10^{-3}[/tex])

      [tex]\Delta P[/tex] = 100 Pa,       F = ?

Therefore, formula to calculate force is as follows.

              F = [tex]\Delta P \times A[/tex]       (as A = [tex]\pi \times r^{2}[/tex])

so,          F = [tex]\Delta P \times \pi \times r^{2}[/tex]

                 = [tex]100 Pa \times 3.14 \times (10^{-2})^{2}[/tex]

                 = [tex]3.14 \times 10^{-2}[/tex] N

Thus, we can conclude that net force on the blood in this section of artery is [tex]3.14 \times 10^{-2}[/tex] N.