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nough of a monoprotic acid is dissolved in water to produce a 0.0199 M solution. The pH of the resulting solution is 2.64 . Calculate the K a for the acid.

Respuesta :

Answer:

Explanation

pH = 2.64

pH = - log [H+]

[H+] = 0.00229 M

HA = 0.0199 M

Dissociation equation

HA --> H+ + A-

Ka = [H+][A-]/[HA]

[H+] = [A-]

Ka = (0.00229^2)/0.0199

= 2.64 × 10^-4 M

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