Answer:
7923.6 g of (NH₄)₂SO₄ can be produced by this reaction
Explanation:
The reaction is:
2NH₃ (aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
In this reaction ratio is 1:1.
As the ammonia is in excess, the limiting reagent is the sulfuric acid.
So 1 mol of sulfuric can produce 1 mol of sulfate
Then, 60 moles of sulfuric must produce 60 moles of sulfate.
We convert the moles to mass:
60 mol . 132.06 g / 1mol = 7923.6 g
