Answer : The mass of lead in 139 g of [tex]Pb(NO_3)_2[/tex] is, 86.9 grams.
Explanation : Given,
Mass of [tex]Pb(NO_3)_2[/tex] = 139 g
Molar mass of [tex]Pb(NO_3)_2[/tex] = 331.2 g/mol
Molar mass of Pb = 207.2 g/mol
Now we have to calculate the mass of lead.
As, 331.2 g of [tex]Pb(NO_3)_2[/tex] has 207.2 g of lead
So, 139 g of [tex]Pb(NO_3)_2[/tex] has [tex]\frac{139}{331.2}\times 207.2=86.9g[/tex] of lead
Thus, the mass of lead in 139 g of [tex]Pb(NO_3)_2[/tex] is, 86.9 grams.
The mass of lead (Pb) in 139 g of Pb(NO3)2 is 86.96 grams
The standard molar mass of Pb(NO3)2 is:
= [207.2 + (14 × 2) + (16 × 3 × 2) ] g/mol
= 331.2 g/mol
∴
In 331.2 g/mol of Pb(NO3)2, the molar mass of Pb is 207.2 g/mol
Now, to determine the mass of lead in 139 g of PB(NO3)2, we have:
[tex]= \mathbf{\dfrac{139 \ g \times 207.2 \ g/mol}{331.2 \ g/mol}}[/tex]
= 86.96 grams
Therefore, we can conclude that the mass of lead in 139 g of Pb(NO3)2 is 86.96 grams
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