Answer:
[tex]\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex] (1)
The margin of error is given by:
[tex] ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]
And we can reduce this margin of error with:
Increasing the sample size
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
[tex]\sigma[/tex] represent the population standard deviation
n represent the sample size
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex] (1)
The margin of error is given by:
[tex] ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}
And we can reduce this margin of error with:
Increasing the sample size