Answer:
a) (76.21,83.79)
b) (77.32,82.68)
c) Interval decreases
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 60
Sample mean = 80
Sample standard Deviation, s = 15
a) 95% Confidence interval:
[tex]\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}[/tex]
Putting the values, we get,
[tex]z_{critical}\text{ at}~\alpha_{0.05} = 1.96[/tex]
[tex]80 \pm 1.96(\dfrac{15}{\sqrt{60}} ) = 80 \pm 3.79 = (76.21,83.79)[/tex]
b) Sample size, n = 120
95% Confidence interval:
[tex]80 \pm 1.96(\dfrac{15}{\sqrt{120}} ) = 80 \pm 2.68 = (77.32,82.68)[/tex]
c) As observed increasing the sample size, the confidence interval become smaller.