Answer:
Her angular velocity when tucked is greater than when straight by a factor of 0.23
Explanation:
Moment of inertia (I) = mr^2 = mv^2/w^2
m is mass of the diver
v is diver's linear velocity
w is her angular velocity
When straight, I = 14 kg.m^2
mv^2/w^2 = 14
w^2 = mv^2/14
w = sqrt(mv^2/14) = 0.27sqrt(mv^2)
When tucked, I = 4 kg.m^2
w^2 = mv^2/4
w = sqrt(mv^2/4) = 0.5sqrt(mv^2)
Her angular velocity when tucked is greater than when straight by 0.23 (0.5 - 0.27 = 0.23)
