Respuesta :
Answer:
52.1 g is the maximum mass of CO₂, that can be produced by this combustion
Explanation:
Mass of Octane: 63 g
Mass of O₂: 59.4 g
This is a combustion reaction where the products, are always water and CO₂. We define the equation:
2C₈H₁₈ (l) + 25O₂(g) → 16CO₂(g) + 18H₂O(g)
As we have, both mases of each reactant, we must define which is the limiting reagent. We convert the mass to moles:
63 g. 1mol / 114g = 0.552 moles
59.4 g . 1mol / 32g = 1.85 moles
Certainly, the limiting reagent is the oxygen:
2 moles of octane need 25 moles of O₂ to react
Therefore, 0.552 moles of octane must need (0.552 . 25) /2 = 6.9 moles of O₂ (I do not have enough moles of oxygen, I need 6.9 and I only got 1.85 moles)
When we know the limiting reagent we can do the calculations with the stoichiometry of the reaction:
25 moles of O₂ can produce 16 moles of CO₂
Therefore, 1.85 moles of O₂ may produce (1.85 . 16) /25 = 1.18 moles.
We convert the moles to mass to get the final answer:
1.18 mol . 44 g / 1mol = 52.1 g
Answer:
The mass of carbon dioxide produced is 52.3 grams
Explanation:
Step 1: Data given
Mass of octane = 63.0 grams
Mass of oxygen = 59.4 grams
Molar mass of octane = 114.23 g/mol
Molar mass of oxygen = 32.0 g/mol
Step 2: The balanced equation
2C8H18 + 25O2 → 16CO2 + 18H2O
Step 3: Calculate moles
Moles = mass / molar mass
Moles octane = 63.0 grams / 114.23 g/mol
Moles octane = 0.5515 moles
Moles oxygen = 59.4 grams / 32.0 g/mol
Moles oxygen = 1.856 moles
Step 4: Calculate limiting reactant
For 2 moles octane we need 25 moles oxygen to produce 16 moles CO2 and 18 moles H2O
Oxygen is the limiting reactant. IT will completely be consumed (1.856 moles). Octane is in excess. There will react 1.856 / 12.5 = 0.1485 moles
There will remain 0.5515 -0.1485 = 0.403 moles octane
Step 5: Calculate mass of CO2
For 2 moles octane we need 25 moles oxygen to produce 16 moles CO2 and 18 moles H2O
For 1.856 moles O2 we'll have 16/25 * 1.856 = 1.1878 moles CO2
Step 6: Calculate mass of CO2
Mass of CO2 = moles CO2 * molar mass CO2
Mass of CO2 = 1.1878 moles * 44.01 g/mol
Mass of CO2 = 52.3 grams
The mass of carbon dioxide produced is 52.3 grams
