Respuesta :
Answer:
So the present mass will be 0.0017002 times of the initial mass of the sample.
Explanation:
Given:
- half life of the given sample, [tex]t'=5\times 10^8\ yrs[/tex]
- We know that solar system came in to existence approximately [tex]4.6\times 10^{9}[/tex] years ago.
Let the initial quantity on the formation of the solar system be, [tex]m_o[/tex]
Then the final quantity at present be:
[tex]m=m_o\times (\frac{1}{2})^{(t/t')}[/tex]
[tex]m=m_o\times (\frac{1}{2} )^{4.6\times 10^9\div(5\times 10^8)}[/tex]
[tex]m=m_o\times 0.0017002[/tex]
So the present mass will be 0.0017002 times of the initial mass of the sample.
