Explanation:
The given data is as follows.
[tex]V_{1}[/tex] = 120 V, [tex]V_{2}[/tex] = 6.50 V
[tex]N_{1}[/tex] = 400, [tex]N_{2}[/tex] = ?
Formula to calculate the number of turns in secondary coil are as follows.
[tex]\frac{N_{1}}{N_{2}} = \frac{V_{1}}{V_{2}}[/tex]
Putting the given values into the above formula as follows.
[tex]\frac{N_{1}}{N_{2}} = \frac{V_{1}}{V_{2}}[/tex]
[tex]\frac{400}{N_{2}} = \frac{120}{6.50}[/tex]
[tex]N_{2}[/tex] = 21.66
= 22 (approx)
Thus, we can conclude that number of turns in the secondary coil are 22.
