Option B:
Equation of a line is
[tex]$y-6=\frac{-3}{2} (x-2)[/tex]
Solution:
Equation of a parallel line:
3x + 2y = 5
2y = –3x + 5
[tex]$y=\frac{-3x}{2}+\frac{5}{2}[/tex]
Slope of this line, [tex]m_1=\frac{-3}{2}[/tex]
If two lines are parallel, then slopes of their lines are equal.
[tex]m_1=m_2[/tex]
[tex]m_2=\frac{-3}{2}[/tex]
The line passes through the point (2, 6)
Point-slope formula:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]$y-6=\frac{-3}{2} (x-2)[/tex]
This is the equation of the line.
Option B is the correct answer.
