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A Carnot refrigerator is operated between two heat reservoirs at temperatures of 320 K and 270 K. (a) If in each cycle the refrigerator receives 415 J of heat energy from the reservoir at 270 K, how many joules of heat energy does it deliver to the reservoir at 320 K

Respuesta :

Answer:

Qh = -491.85J

(It is negative due to rejected heat)

Explanation:

In the question, the heat received by the refrigerator is at the cold reservoir where Qc= 415J

Now, we are looking for Qh.

Thus, using thermodynamics equation, we have;

Qc/Qh = — Tc/Th

Making Qh the subject, we obtain ;

-(QcTh)/Tc = Qh

Plugging in the relevant values, we obtain ;

-(415x320)/270 = - 132800/270 =

- 491.85J

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