A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60 to a uniform electric field of magnitude 14 N>C. (a) Find the magnitude of the electric flux through the sheet. (b) Does the answer to part (a) depend on the shape of the sheet

Respuesta :

Answer:

a. 1.75 Nm²/C

b. Yes.

Explanation:

a. Electric Flux is given as:

Φ = E*A*cosθ

Where E = electric flux

A = Surface area

Φ = 14 * 0.25 * cos60

Φ = 1.75 Nm²/C

b. Yes, the shape of the sheet will affect the Flux through it. This is because flux is dependent on area of the surface and the area is dependent on the shape of the surface.

(a) The flux through the sheet is [tex]1.75 Nm^2/C[/tex]

(b) Yes the electric flux depends on the shape of the sheet.

Electric Flux:

(a) Electric Flux is given by

[tex]\phi = EAcos\theta[/tex]

Where E = electric field

A = Surface area

and θ = 60

[tex]\phi = 14\times0.25\times cos60\\\\\phi = 1.75 Nm^2/C[/tex]

(b) Since the electric flux is dependent on the area of the surface and the shape of the surface will affect the area of the sheet, therefore the electric flux will also be affected by the shape of the sheet.

Learn more about electric flux:

https://brainly.com/question/7944455?referrer=searchResults