The statements 2, 4, and 5 are correct about the right-angled triangle.
Step-by-step explanation:
Step 1:
The formulae needed to solve the problem are;
[tex]sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacent side}{hypotenuse}, tan\theta = \frac{opposite side}{adjacentside},[/tex]
[tex]cosec\theta = \frac{hypotenuse}{oppositeside} , sec\theta = \frac{hypotenuse}{adjacent side}, cot\theta = \frac{adjacent side}{oppositeside}.[/tex]
Step 2:
If the angle is B, the opposite side measures 5 units, the adjacent side measures 12 units, and the hypotenuse measures 13 units.
[tex]cos B = \frac{12}{13} , sec B = \frac{13}{12} .[/tex]
Step 3:
If the angle is A, the opposite side measures 12 units, the adjacent side measures 5 units, and the hypotenuse measures 13 units.
[tex]cot A = \frac{5}{12} , cosecA = \frac{13}{12} , sinA =\frac{12}{13} , tan A = \frac{12}{5}[/tex].
Of the six given options, options [tex]cot A = \frac{5}{12}, sinA =\frac{12}{13} ,sec B = \frac{13}{12}[/tex] are the right options.
