The area of the sector is 5.89 m²
Explanation:
Given:
Central angle of the arc, α = 75°
Diameter of the circle, d = 6 m
Radius of the circle, r = 3m
Area of the sector, A = ?
We know:
[tex]Area = \frac{\alpha }{360} X \pi r^2[/tex]
On substituting the value we get:
[tex]Area = \frac{75}{360} X 3.14 X (3)^2\\\\A = 5.89 m^2[/tex]
Therefore, the area of the sector is 5.89 m²
